The expression lod3 (8-x) is defined for all values of x such as

The weight of a Great blue heron, a type of bird, can grow to around 4 pounds, but can vary. Let W be a random variable that rep

hammer [34]

Answer:

10 ≥ w ≥ 9 ( ? )

Step-by-step explanation:

the probability that a Great blue heron is at least 9 pounds, but no more than 10 pounds -> w= weight of great blue heron

w is at lest 9 pound's -> w ≥ 9

w is no more than 10 pound's -> w ≥ 10

w ≥ 9 ( + ) w ≥ 10 = 10 ≥ w ≥ 9

6 0

4 years ago

a landscaping company counted 51 invoices for tree services at the end of the month. they charge $375 for a tree installation an

Radda [10]

We used the elimination method to find the ordered pair, (x,y), that represents the situation is (12,39).

Number of invoices = 51

Charge for tree installation = $375

Charge for tree trimming = $54

Total amount in invoices = $6,606

Let x and y represent number of installations and number of trimmings respectively.

Hence,

x + y = 51 ...(1)

375x + 54y = 6606

3 (125x + 18y) = 3*2202

125x + 18y = 2202 ...(2)

Multiplying (1) by 18, we get

18x + 18y = 918 ...(3)

(2) - (3)

107x + 0 = 1284

x = 1284/107 = 12

Hence,

y = 51 - 12 = 39.

To learn more about elimination method, here:-

brainly.com/question/13877817

#SPJ4

3 0

1 year ago

Which expression is equal to 4-6

frez [133]

-1-1 or 2-4 or 3-5 or 6-8 or 7-9 or 8-10

6 0

3 years ago

Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr

Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0

3 years ago

Nicole runs a farm stand that sells bananas and peaches. Each pound of bananas sells for $2 and each pound of peaches sells for

stepan [7]

Answer:

The required system of equations is:

2x + 3.25y = 231.75

x = y + 3

where x is the number of pounds of bananas and y is the number of pounds of peaches

Explanation:

1- Defining the variables:

Assume that the number of pounds of bananas sold is x

Assume that the number of pounds of peaches sold is y

2- Setting the system of equations:

We are given that:

i. Each pound of bananas sells for $2

Money gained from selling x pounds of bananas is 2x

ii. Each pound of peach sells for $3.23

Money gained from selling y pounds of peaches is 3.25y

iii. Nicole made $231.75 in total. This means that:

2x + 3.25y = 231.75 .................> equation I

iv. Nicole sold 3 more pounds of bananas than pounds of peaches. This

means that:

pounds of bananas = pounds of peaches + 3

x = y + 3 ..................> equation II

3- Solving the equations (if required):

In equation II, we have: x = y + 3

Substitute with equation II in equation I and solve for y as follows:

2x + 3.25y = 231.75

2(y+3) + 3.25y = 231.75

2y + 6 + 3.25y = 231.75

5.25y = 231.75 - 6

5.25y = 225.75

y = 43

Substitute with y in equation II to get x:

x = y + 3

x = 43 + 3 = 46

Based on the above:

Number of pounds of bananas = x = 46 pounds

Number of pounds of peaches = y = 43 pounds

Hope this helps :)

4 0

3 years ago