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gogolik [260]
3 years ago
14

Pretty pls help me :3

Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0

Answer:

You can do 60 ÷ 6 = 10 groups.

Step-by-step explanation:

There are many ways to answer this and it's very simple.

6 and 10 is just one of the many factors of 60.

you can also do 60 ÷ 2 = 30 groups

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The point (2,-5) is reflected over the y-axis. Which of the following points is the image?
docker41 [41]
2,5 would be the answer
7 0
3 years ago
Wot it's the missing number x9=6x3
vivado [14]
If i'm understanding this question correctly, i believe that it's 2. 
2*9=6*3
4 0
3 years ago
Read 2 more answers
Please solve this question and explain it and how to do it: What is the slope of the line 2 - y = 8x
Schach [20]

Answer:

The slope is : -8/1

Step-by-step explanation:

2-y=8x

We need to get “y” by itself , so subtract “ 2 “ from both sides

-y=8x-2

Then we still have to get “ y” by itself , but it’s Negative “y” now! Divide both sides by “ negative one “ (-y is just like -1y).

-y/-1 = 8x/-1 (-2/-1)  

* I put the -2/-1 on () just to organize it *

y = -8x +2

2: y-intercept

-8: slope

[ y = -8x + 2 ] and this called the y-intercept form .✨


4 0
2 years ago
The radius is 9 cm. what is the approximate circumference of the circle
Mumz [18]

Answer:

56.5487 (this is exact, just round it if you want)

Step-by-step explanation:

The formula to find the circumference is 2, pi, r (radius).

4 0
2 years ago
A rectangular swimming pool has a length twice as long as its width. The pool has a sidewalk around it that is 2 feet wide. Writ
xxMikexx [17]

Answer:

A_p=2w^2

A_s=12w+16

Step-by-step explanation:

Functions and Geometry

Sometimes we need to express areas, volumes, and distances in terms of unknown quantities (or variables). When we can find such expressions, they can be referred to as functions. Let's recall the area of a rectangle is A=wl, being w its wide and l its length

Please refer to the image below. The length of the swimming pool is l and its width is w. Its area is

A_p=lw

We know the length is twice as long as its width, l=2w, so

A_p=(2w)w=2w^2

A_p=2w^2

The sidewalk is 2 feet wide. The length of the pool and its sidewalk is

l'=l+4

Similarly, the width of the pool+sidewalk is

w'=w+4

The area of the pool+sidewalk is

A'=l'w'=(l+4)(w+4)=lw+4l+4w+16

We know that l=2w, so

A'=(2w)w+4(2w)+4w+16

A'=2w^2+12w+16

The area of the sidewalk alone is the subtraction of both areas

A_s=A'-A_p=2w^2+12w+16-2w^2

Simplifying

A_s=12w+16

7 0
3 years ago
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