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tekilochka [14]
3 years ago
15

Write the equation of the line that has the indicated slope and contains the indicated point. Express the final equation in stan

dard form. M=1/2, (6,8)
Mathematics
1 answer:
OlgaM077 [116]3 years ago
7 0

Answer:

y = 1/2x + 5

Step-by-step explanation:

Given :

Slope, m = 1/2

(x1, y1) = (6, 8)

y - y1 = m(x - x1)

y - 8 = 1/2(x - 6)

y - 8 = 1/2x - 3

y - 8 + 8 = 1/2x - 3 + 8

y = 1/2x + 5

Stamdard form of equation :

y = mx + c

Hence, equation is :

y = 1/2x + 5

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I need help on this.
tatiyna

9514 1404 393

Answer:

  (a)  $1430

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Step-by-step explanation:

(a) The debit card is funded by Jenny's checking account, so it cannot be used to spend more than her checking account balance. The most Jenny can spend using her debit card is $1430.

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(b) Amounts purchased using her credit card add to the credit balance. The most Jenny can purchase is the difference between her current balance and her credit limit.

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5 0
3 years ago
Adding the fractions<br><br> 3/14+2/21+1/6
NARA [144]

Answer:

\frac{10}{21}

Step-by-step explanation:

The LCM of 14, 21 and 6 is 42

We require to change the fractions to fractions with a denominator of 42

\frac{3(3)}{14(3)} + \frac{2(2)}{21(2)} + \frac{1(7)}{6(7)}

= \frac{9}{42} + \frac{4}{42} + \frac{7}{42} ← add the numerators, leaving the denominator

= \frac{9+4+7}{42}

= \frac{20}{42} ← divide both values by 2

= \frac{10}{21} ← in simplest form

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The value of x is 13 for the first attachment. 
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Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
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