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rodikova [14]
3 years ago
10

Let sin(45°)=0.7071.Enter the angle measure (μ), in degrees for cos(μ)=−0.7071.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Given :

Let sin(45°)=0.7071.

To Find :

The angle measure (μ), in degrees for cos(μ)=−0.7071 and value equivalent to 360n + , where n is an integer .

Solution :

We know , value of sin x and cos x is same at x = 45° .

Now , cos (-x) = cos(90°+x)

Therefore , μ in given question is :

μ =90°+45°

μ=135°

So , for angle of type 360°n + :

μ = 360°n + 135° .

Hence , this is the required solution .

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Answer:

The original price of the tent = $320

Step-by-step explanation:

Let the original price be =$ x

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Discount = Original price - Sale price = $80

So, we have

0.25x=80

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The two dot plots compare ages of girls and boys in a pottery class.
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Ludmilka [50]

Answer:

<em>a. This option is correct</em>

<em>b. This will be true only if we take the </em><em>mode</em><em> as the best representative value </em>

c. <em>This is a correct choice</em>

<em>d. This is not a correct choice</em>

Step-by-step explanation:

<u>Statistics</u>

We are given a dot plot representing 30 random sample proportions of high school students about their sports activities. Based on the data extracted from the plot, we can make some basic conclusions and, less accurately, some predictions.

From the data plot we can see that the following proportions were obtained, along with their absolute frequencies:

0.05 -> 3

0.10 -> 8

0.15 -> 7

0.20 -> 5

0.25 -> 4

0.30 -> 2

Let's select which of the following options are correct

a. A sample proportion of 0.20 means that 4 of 20 high school students responded that they play a sport.

The ratio between the sport playing students to the total of high school students is

\displaystyle \frac{4}{20}=\frac{1}{5}=0.20

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\bar x\approx 0.16

<em>This is a correct choice</em>

d. The shape of the sample distribution is fairly symmetrical

We can see the distribution if left-skewed because its peak value is not at the mean value. The mode and the mean are fairly different, thus this choice is not correct

5 0
3 years ago
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