Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
The degree of the polynomial will tell you the max amount of zeros you will have. 11 in this case.
However you can also have 9,7,5,3,1 (keep subtracting by 2)
So the answer is 1.
If the triangle was a right triangle, then you can use the Pythagorean theorem to find the lengths.
Answer:
Step-by-step explanation :4.0148 rounded to the nearest thousand is 0, but if you meant rounded to the nearest thousandth, it would be 4.015 because the 8 in the ten thousandth column would cause the 4 in the thousandth column to round up to 5.
