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Aliun [14]
3 years ago
13

What is the value of x in the equation? 2/3 (x + 6) = -18

Mathematics
2 answers:
Law Incorporation [45]3 years ago
4 0
The answers to the question is -33
bezimeni [28]3 years ago
3 0
-33 is the right answer
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Explain how to find the missing exponent given the base and the value
drek231 [11]

Answer:

To find the value of missing exponent, we have to split the number which is in other side of equal sign (which is not having power) as the multiple of base of the missing exponent.

On both sides, powers have the same base, so their exponents must be equal.

Step-by-step explanation:

<h3>Problem 1:</h3>

Write the missing exponent:

25=5^x

Let x be the missing exponent.

To find the value missing exponent, we have to split the number which is in the left side as the multiple of the base of the missing exponent.

That is,

25=5*5 or 5^2

Now,

5^2=5^x

Powers have the same base so their exponent must be equal.

Hence the missing exponent is 2

6 0
3 years ago
1. An orange is peeled . 18 identical sectors are found . What angle do does each semicircular surface make with another in a wh
KatRina [158]

Answer:

<h3>#1</h3>

<u>Since the circle covers 360°, each sector will be:</u>

  • 360°/18 = 20°

The same angle will be made between two adjacent semicircles.

<h3>#2</h3>

The points have same latitude but different longitude.

35°W and 15° are at different sides from zero longitude.

<u>The difference is:</u>

  • 35° + 15° = 50°
8 0
3 years ago
The triangles shown below must be congruent. right awnsers only please.
tankabanditka [31]
It is true. The triangles are congruent.
8 0
3 years ago
Read 2 more answers
9(x + 1) = 25 + x<br><br> x = 2<br> x = 3<br> x = 4<br> x = 5
wolverine [178]

Answer:

2

Step-by-step explanation:

9x + 9 = 25 + x

8x = 16

x = 2

make sure to ask if you need any further guidance.

5 0
2 years ago
Read 2 more answers
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
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