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SVETLANKA909090 [29]
3 years ago
6

The price of XYZ stock fluctuates widely. In January it closed at $3.50 but In February it Closed at $2.25. However at the end o

f March it shot back up to $5.00.
What was the average monthy change in the price of XYZ stock from january through march?
​
Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

$3.583

Step-by-step explanation:

Given the monthly stock prices :

January = $3.50

February = $2.25

March = $5.00

The average monthly change in price of XYZ stock from. JANUARY through MARCH is;

(January + February + March) / 3

Average monthly change :

(3.50 + 2.25 + 5.00) / 3

$10.75 / 3

= $3.583

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borishaifa [10]

Answer:

46.3

Step-by-step explanation:

Mean is the average of all values. You add all the values on the table and divide them by the amount of values (here there are 10 land animals so you would divide by 10).

\frac{70+61+50+48+45+43+40+39+35+32}{10} =\frac{463}{10} = 46.3

5 0
3 years ago
Please I need help this is due tomorrow and I'm falling behind :(:
Rama09 [41]
This answer to your is 17
4 0
3 years ago
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LALLY MANLLITYONLILULIVE
uysha [10]
B 9x+10, this is because you just simply combine like terms
5 0
3 years ago
Three hundred new ones cost $2100. what would be the cost of 120 new ones​
SSSSS [86.1K]

Answer:

840

Step-by-step explanation:

120 is 40% of 300, and 840 is 40% of 2100 is 840.

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3 years ago
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A riverboat travels 54 km downstream in 2 hours. It travels 57 km upstream in 3 hours. Find the speed of the boat and the speed
irakobra [83]

Here we must write and solve a system of equations to find the speed of the boat and the speed of the stream. We will find that the boat's speed is 23km/h and the river's speed is 4km/h.

First, remember the relation:

Distance = Speed*Time.

Now let's define the variables we will be using:

  • B = boat's speed
  • R = river's speed.

When the boat travels downstream, the total speed of the boat is the speed of the boat plus the speed of the river, and we know that in that case it travels 54km in 2 hours, then:

54km = (B + R)*2h

When the boat travels upstream, we must subtract the speed of the river. In that case, we know that the boat travels 57km in 3 hours, then we have:

57km = (B - R)*3h

Then our system of equations is:

54km = (B + R)*2h

57km = (B - R)*3h

To solve this, first, we need to isolate one of the variables in one of the equations, let's isolate B in the second one:

57km = (B - R)*3h

57km/3h + R = B

19 km/h + R = B

Now we can replace that in the other equation:

54km = (B + R)*2h

54km/2h = B + R

27 km/h = B + R = (19 km/h + R) + R

Now we can solve this for R:

27 km/h = 19km/h + 2*R

27 km/h - 19km/h = 2*R

8 km/h = 2*R

(8km/h)/2 = 4km/h = R

Now that we know the value of R, we can use:

B = 19 km/h + R  = 19 km/h + 4km/h = 23 km/h

So the boat's speed is 23km/h and the river's speed is 4km/h.

If you want to learn more, you can read:

brainly.com/question/12895249

5 0
3 years ago
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