Explanation:
(3) active transport
The molecules would be moving against their concentration gradient from a region of low concentration to a region of high concentration.
While cells facilitate the transport of molecules via movement across the cell membrane, there many different mechanisms. These include passive diffusion, facilitated diffusion, and passive transport. However some very large molecules require specialized type of active transport, which requires energy in the form of ATP, in order to move substances across the membrane against their concentration gradient.
Active transport is a mediated process that requires an energy input and the use of specialized membrane proteins to move against the concentration gradient. These proteins require energy in the form of adenosine triphosphate or ATP in order to facilitate necessary conformational changes to the large protein molecules to alter the spatial location of the molecule. For instance, with Na+, K+ pumps in cell membranes.
Learn more about membrane components at brainly.com/question/1971706
Learn more about plasma membrane transport at brainly.com/question/11410881
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Banana peels can be decomposed by bacterial action, so they are biodegradable.
Explanation:
La energía es Consumidor como Animales y Plantas utiliza la energía para los procesos de la vida y se trasforma en Calor
A polar molecule has a positive and negative end because of electronegativity.
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".