Answer:
A,C,D
...............................
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
If you divide each number by the previous one, you get:
-86 / -172 = 1/2
-43 / -86 = 1/2
-21.5 / -43 = 1/2
The common ratio is 1/2 = 0.5
To solve the problem we must know the basic exponential properties.
<h3>What are the basic exponent properties?</h3>
![\sqrt[m]{a^n} = a^{\frac{n}{m}}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Ba%5En%7D%20%3D%20a%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D)
The expression can be written as ![x^9\sqrt[3]{y}](https://tex.z-dn.net/?f=x%5E9%5Csqrt%5B3%5D%7By%7D)
.
Given to us
Using the exponential property,
Using the exponential property ,
![=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}](https://tex.z-dn.net/?f=%3Dx%5E9%5Ctimes%20y%5E%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5C%3Dx%5E9%5Ctimes%20%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C%3Dx%5E9%20%5Csqrt%5B3%5D%7By%7D)
Hence, the expression can be written as .
Learn more about Exponent properties:
brainly.com/question/1807508
Answer: girls=20, sister=10
Step-by-step explanation:
Let x = the girl's sister's age (present)
Let 2x= the girl's age (present)
-------------------------------------------------------------
According to the question
(x+5)(2x+5)=375
Expand parentheses by FOIL (First Outer Inner Last)
2x²+5x+10x+25=375
Combine like term (5x and 10x)
2x²+15x+25=375
Subtract 375 on both sides
2x²+15x+25-375=375-375
2x²+15x-350=0
Find the factors (cross factor)
(x-10)(x+17.5)=0
x=10 or x=-17.5 (rej) ⇔ the age can't be negative
the girl's age is 20, and her sister's age is 10.
