You would just subtract/add like you normally would from left to right because its a subtract and add operation.
Hope that helps :)
Answer:
Step-by-step explanation:
Attached above
Quotient : 5x + 8 Remainder : 14x2 + 5x + 11
Answer: There are 12 white and blue cars more than silver and red cars
Number of white cars: n1=25
Number of blue cars: n2=17
Number of white and blue cars: n3=n1+n2=25+17→n3=42
Number of silver cars: n4=21
Number of red cars: n5=9
Number of silver and red cars: n6=n4+n5=21+9→n6=30
How many more white and blue cars are there than silver and red cars?
n=?
n=n3-n6=42-30→n=12
Answer: There are 12 white and blue cars more than silver and red cars.
Answer:
D is your answer
Step-by-step explanation:
y = x - 3
y = 2
x = 5
now insert the x and y into the equation
2 = 5 - 3
then subtract
2 = 2
last to find out if your right when both numbers equal each other like 2 = 2 then that will be you answer to your problem
