A factor tree for 61 that is not nothing
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Answer:
Step-by-step explanation:
We cannot factor this function out which tells us that there are no zeros. The graph backs this up because we can see that there are none. The easiest way to graph this would start by plugging in points and making a table for yourself.
Lets start by plugging in -1.
(-1)^2-2(-1)+3 =6, this means we have a point at (-1,6).
Now lets plug in 0.
(0)^2-2(0)+3= 3 (0,3)
For plugging in 1
(1)^2-2(1)+3=2 (1,2) (this happens to be the vertex)
And lastly lets plug in 2
(2)^2-2(2)+3=3 (2,3)
Depending on how many points are needed, keep plugging in numbers like we did above.
