Answer: X = 10.20240940...
Step-by-step explanation:
x(2x + 9) = 2x^2 + 9x
2x^2 + 9x = 300
- 300 ON BOTH SIDES
2x^2 + 9x - 300 = 0
SOLVE USING THE QUADRATIC FORMULA
x = -b +/- all root (b)^2 - 4(a)(c) All over 2(a)
When all the values are plugged in:
When using "+" in the equation you should get:
x = 10.20240940…
When using "-" in the equation you should get:
x = −14.70240940…
Now.. you CANNOT have a negative length, so you cross of the negative value leaving you one value for x which is 10.20240940...
YOUR ANSWER IS: x = 10.20240940...
If the square has the side s, and area A=324
then s=√324=18
the side of the square is 18cm
To prove two equations have infinite solutions, you have to prove that those two equations are the same equations, but in a different form.
For example: Prove the equations are infinite
5y=2x+7
10y=4x+14
If you multiply the first equation by 2, and substitiute any of the numbers, you will get 0=0
Hi friend,
((5+a)/a)/((a^2 -25) /5a)
=(a+5)/((a^2 - 25)/5)
=(a+5)(5)/(a+5)(a-5)
=5/(a-5)
Therefore your answer is B)
Hope this helps you!
Your answer is zero because you do 4*4=16*3=48*0=zero your answer
hope this helps you
