Answer:
x = 25
Step-by-step explanation:
Since the triangles are congruent then corresponding angles are congruent.
That is ∠ D and ∠ B are corresponding angles and congruent, thus
4x - 20 = 2x + 30 ( subtract 2x from both sides )
2x - 20 = 30 ( add 20 to both sides )
2x = 50 ( divide both sides by 2 )
x = 25
Answer:
y=3x + 1
Step-by-step explanation:
slope is same
insert coordinates into x and y values
determine y-intercept
Answer:
46
Step-by-step explanation:
We are given that a class's test scores are normally distributed with an average score of 60.
We know that the curve of a normal distribution is symmetric about its mean.
60-14=46
60+14=74
Hence, the point 46 lies to the left of the mean and 74 lies to the right of the mean, and the two points have the same function value.
Left one is linear and the one on the right is nonlinear
Part 1: Answer:
(x+1)(x+1)(x-6) = x^3 - 4x^2 - 11x - 6
Step-by-step explanation:
To make r a root, include (x-r) as a factor. (-1+1)(-1+1)(-1-6) is zero even though (-1-6) isn't.
(6+1)(6+1)(6-6) is zero.
Part 2 Answer:
Standard form: y = -x^4 + 12
Degree 4
left end goes down, right end goes down.
Step by step: apply the definitions of standard form, polynomial degree, and "end behavior". In other words, read the textbook.
Part 3: Answer: x = 3, x = 8
Step by step:
x^2-11x = -24
x^2-11x+24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8
Part 4a Answer:
quotient 2x^2 + x - 3
remainder 1
Step by step:
2x^2 + x - 3
___________________
x-4 ) 2x^3 - 7x^2 - 7x + 13
2x^3 - 8x^2
__________
0 + x^2 - 7x + 13
x^2 - 4x
____________
0 - 3x + 13
- 3x + 12
______
1
Part 4b answer:
quotient 2x^2 - 6x + 2
remainder -20
Step by step: you have to know exactly what you are doing. Refer to textbook or Wikipedia.
dividend 2x^3 +14x^2 - 58x
divisor x+10
leading coefficient of divisor must be 1
write coefficients of dividend at top
write coefficients of dividend at left
| 2 14 -58 0
-10 | -20 60 -20
___________
| 2 -6 2 -20
Coefficients of quotient are 2 -6 2
Remainder is -20
quotient = 2x^2 - 6x + 2
