Step-by-step explanation:
follow the steps in the picture. I've started it for you all you need to do is finish
A.
this is assuming it grows by 20% of the houses it has at that time (compound interest)
A(x)=30(1.2)ˣ⁻¹ or A(x)=25(1.2)ˣ
B(x)=3(x-1)+45 or B(x)=3x+42
B.
A(5)=62.28 or about 62 homes
B(5)=60
C.
this is tricky so I think it should have been only 20% of 30
start over
A.
20% of 30=6
A(x)=6(x-1)+30 or A(x)=6x+24
B(x)=3(x-1)+45 or B(x)=3x+42
B.
A(5)=54 homes
B(5)=60
C.
6x+24=3x+42
minus 3x
3x+24=42
minus 24 both sides
3x=18
divide by 3
x=6
after 6 years
both will have 63 homes
-my/m-4
.....
Have a noice day
Answer:
Arithmetic sequence
f(n) = 5n + 2
Step-by-step explanation:
f(1) = 7
f(2) = 7 + 5
f(3) = 7 + 5 + 5 = 7 + (2)(5)
f(n) = 7 + (n-1)(5)
f(n) = 7 + 5n - 5
f(n) = 5n + 2
Answer:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of .
Out of 100 people sampled, 42 had kids.
This means that
99% confidence level
So , z is the value of Z that has a p-value of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).