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natka813 [3]
3 years ago
13

A car travels 1.9 miles from Point A to Point B. The car then turns at Point B and travels 1 mile to Point C, before heading bac

k to Point A. The distance from Point C to Point A is 1.4 miles. If the car's path is represented by a triangle, what degree of turn did the car make, at Point B?
Mathematics
1 answer:
tamaranim1 [39]3 years ago
3 0
If you represent the problem in a diagram, you will form a triangle with 3 known length of the sides. When you are given all sides, and you are asked to find an angle, you can use the cosine law.

b^2 = a^2 + c^2 - 2ac*cosB
1.4^2 = 1.9^2 + 1^2 - 2(1.9*1)(cosB)
B = 45.78°


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Answer:

The weight of a small box  = 13.5 kg

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Step-by-step explanation:

Let us assume the weight of a small box = m kg

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Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

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Adding both equation, we get

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⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

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