Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
1 year and 5 months
Step-by-step explanation:
Hello Lexi!
<u><em>Answer: ⇒⇒⇒⇒⇒⇒
</em></u>
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Step-by-step explanation:
First you had to divide by 2 from both sides of equation.

Simplify.


Divide by the numbers.



Apply the fraction rule.


Then you divide by the number.



Add by 4 from both sides of equation.

Simplify it should be the correct answer.

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Hope this helps!
Thank you for posting your question at here on brainly.
Have a great day!
-Charlie
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