Answer:
Step-by-step explanation:
Median: 88
First Quartile: 84
Third Quartile: 92
Interquartile Range: 8
I hope this helps :)
I might not be entirely correct but I believe it is 3/5
See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid
we know that
One edge of the cuboid has length 2 cm-----> <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1
[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]
100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm
<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm
the answer is the length of a diagonal of the cuboid is 13.75 cm
The benchmarks are: 0, 0.25, 0.50, 0.75 and 1.
2. 81 → 2.75
+
3.73 → 3.75
------------
2.75 + 3.75 = 6.50
Answer:

Step-by-step explanation:
{y = 6x − 11
{y = x² + 4x − 10
x² + 4x − 10 = 6x − 11
- [6x − 11] - [6x − 11]
________________________
x² - 2x + 1
![{[x - 1]}^{2} = 0](https://tex.z-dn.net/?f=%7B%5Bx%20-%201%5D%7D%5E%7B2%7D%20%3D%200)
1 = x [Plug this back into both equations above to get the y-coordinate of −5]; −5 = y
I am joyous to assist you anytime.