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marysya [2.9K]
3 years ago
10

A ladder is leaning up against a 70 foot wall at an angle of elevation of 38° how far is the foot of the latter from the wall? R

ound your answer to the nearest 10th of a foot
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
4 0
Tanα=h/x

x=h/tanα

x=70/tan38 ft

x≈89.6 ft (to nearest tenth of a foot)

Note: the question seems strange, (because this would make the ladder almost 114 feet long!) or are we to assume as I did that the ladder is leaning against a point 70 feet high, or should if be a 70 foot ladder leaning against a wall of unknown height?

If it is just a 70 ft ladder at a 38° inclination the:

cosα=x/L

x=Lcosα

x=70cos38° ft

x≈55.2 ft
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Find the median, first quartile, third quartile, and interquartile range of the data.
serious [3.7K]

Answer:

Step-by-step explanation:

Median: 88

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Third Quartile: 92

Interquartile Range: 8

I hope this helps :)

7 0
3 years ago
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A spider is 6 mm long what fractional part of one centimeter is 6 mm
vladimir2022 [97]
I might not be entirely correct but I believe it is 3/5
5 0
3 years ago
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20 points!!!!!!!
castortr0y [4]
See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid

we know that
One edge of the cuboid has length 2 cm----->  <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1

[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]

100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0

using a graph tool------> to resolve the second order equation
see the attached figure

the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm

<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm

the answer is
 the length of a diagonal of the cuboid is 13.75 cm



4 0
3 years ago
Use benchmarks to estimate 2.81+3.73
love history [14]
The benchmarks are:  0,  0.25,  0.50,  0.75  and 1.
   2. 81   →  2.75
+
   3.73    →  3.75
------------
2.75 + 3.75 =  6.50
5 0
3 years ago
HELP PLZ!
Elza [17]

Answer:

-5 = y

Step-by-step explanation:

{y = 6x − 11

{y = x² + 4x − 10

x² + 4x − 10 = 6x − 11

- [6x − 11] - [6x − 11]

________________________

x² - 2x + 1

{[x - 1]}^{2} = 0

1 = x [Plug this back into both equations above to get the y-coordinate of −5]; −5 = y

I am joyous to assist you anytime.

3 0
3 years ago
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