A pet shop manager wants the same number of birds in each cage. He wants to use as few as cages as possible , but can only have
2 answers:
Answer: There are 7 parakeets and 3 canaries in each cage.
Step-by-step explanation:
Since we have given that
Number of parakeets = 42
Number of canaries = 18
According to question, he wants to use as few as cages as possible , but can only have one type of bird in each cage.
So, H.C.F. of 42 and 18 = 6
So, Number of cages would be 6.
Number of parakeets would be
Number of canaries would be
Hence, there are 7 parakeets and 3 canaries in each cage.
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Answer:
J. The equation has one real solution and two complex solutions.
Step-by-step explanation:
Complex solutions come in pairs, so there can only be an even number of them. So we can rule out G, H, and K.
To find the other roots, we can factor using either long division or grouping. To use long division, see the attached picture. To use grouping:
3x³ − 4x² + x − 10 = 0
3x³ − 6x² + 2x² + x − 10 = 0
3x² (x − 2) + (2x + 5) (x − 2) = 0
(x − 2) (3x² + 2x + 5) = 0
The other factor is 3x² + 2x + 5. The discriminant of this is (2)² − 4(3)(5) = -56. Since the discriminant is negative, the roots are complex.
