Question

A pet shop manager wants the same number of birds in each cage. He wants to use as few as cages as possible , but can only have one type of bird in each cage. If he has 42 parakeets and 18 canaries , how many birds will he put in each cage?

Answer 1

Answer: There are 7 parakeets and 3 canaries in each cage.

Step-by-step explanation:

Since we have given that

Number of parakeets = 42

Number of canaries = 18

According to question, he wants to use as few as cages as possible , but can only have one type of bird in each cage.

So, H.C.F. of 42 and 18 = 6

So, Number of cages would be 6.

Number of parakeets would be

$\dfrac{42}{6}=7$

Number of canaries would be

$\dfrac{18}{6}=3$

Hence, there are 7 parakeets and 3 canaries in each cage.

Answer 2

He would use 3 cages for the canaries (6 in each) and 6 cages for the parakeets (7 in each)