Answer:
The correct answer should be B.
I hope this helps!
-Mikayla
General Idea:
If we have a quadratic function of the form f(x)=ax^{2} +bx+c , then the function will attain its maximum value only if a < 0 & its maximum value will be at x=-\frac{b}{2a} .
Applying the concept:
The height h is modeled by h = −16t^2 + vt + c, where v is the initial velocity, and c is the beginning height of the firecracker above the ground. The firecracker is placed on the roof of a building of height 15 feet and is fired at an initial velocity of 100 feet per second. Substituting 15 for c and 100 for v, we get the function as
.
Comparing the function f(x)=ax^{2} +bx+c with the given function
, we get
,
and
.
The maximum height of the soccer ball will occur at t=\frac{-b}{2a}=\frac{-100}{2(-16)} = \frac{-100}{-32}=3.125 seconds
The maximum height is found by substituting
in the function as below:

Conclusion:
<u>Yes !</u> The firecracker reaches a height of 100 feet before it bursts.
Answer:
Step-by-step explanation:
f(x)=-|x|-2
vertex is (0,-2)
The answer is 7.8
Hope this helps!
Answer: 571
To get this answer, we first need to compute the value of f(4). This happens when we plug x = 4 into f(x)
f(x) = 5x + 4
f(4) = 5*4+4 ... each x replaced with 4
f(4) = 20+4
f(4) = 24
Now replace every 'x' in g(x) with f(4) like so
g(x) = x^2 - 5
g(x) = ( x )^2 - 5
g(f(4)) = ( f(4) )^2 - 5 .... every x replaced with f(4)
g(f(4)) = ( 24 )^2 - 5 ... see note below
g(f(4)) = 576 - 5
g(f(4)) = 571
note: the f(4) on the right hand side of that equation is replaced with 24, because we found earlier that f(4) = 24. In other words, f(4) is the same as 24.