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2 years ago

What is the area of this composite shape?

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

7 0

Area of rectangle = 6 x 7 = 42
area of triangle = 1/2(3)(6) = 9

area of figure = 42 + 9 = 51

answer
51 <span>in²</span>

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Carman spent 42$ on 6 hats how much did each hat cost. Its for my sisters elementary school class and i dont even know the awnse

Travka [436]

Answer: 7

Step-by-step explanation:

Step 1: Since it is asking how much each hat costed. We would divide.

42$ divide 6 = 7$ per hat

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3 years ago

If 1/4c = 1/2d = 4e = 8, what is the value of c + d + e?

Natali5045456 [20]

Answer:c=1/32 d=1/16 e=2

C+d+e=1/32+1/16+2=35/16

Step-by-step explanation:

Solve for c

1/4c =8

C=1/32

1/2d=8

d=1/16

4e=8

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3 years ago

Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

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Vladimir [108]

Draw the shape using the points and then move the entire shape 4 squares right then 5 squares down. then you plot those points. the vertices are the points of the shape. hope this helped

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2 years ago

2y+-1y+-1y+3=-13 solve for y

olasank [31]

Answer:

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