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3 years ago

Find the differential of this function. y=tan*sqrt(t)

1 answer:

7 0

Y = tan (√ t )
We will use chain rule.
( tan x ) ` = sec² x
( √ t ) ` = 1 / 2√t
y ` = sec² (√ t ) · 1 / 2√t
y` = 1/cos² ( √ t ) · 1 / 2√t

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I don’t understand my homework... and don’t go at me I’m an slow learner I never done this... before... but NOTE I already got t

MrRa [10]

Answer:

52 weeks

365 days

10 years

100 years

Step-by-step explanation:

5 0

3 years ago

Which property of addition is used in the expression?<br> 0.5+ (0.4+0.8) = (0.5 +0.4) + 0.8

AfilCa [17]

Commutative property i think

6 0

3 years ago

Read 2 more answers

Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago

A construction company is building the house shown below. They need to use a scale

Svetllana [295]

The height of the building is calculated by representing 1 inch as 8 feet. The final building has a height of 20 feet.

<h3>What is scaling?</h3>

Scaling is the increase or decrease in the height of an object by a scale factor k.

Given that the scale used is:

1 inch = 8 feet. Hence:

Since the height of the building is 2.5 in, hence:

Height of the final building = 2.5 in * 8 ft per 1 in = 20 feet

The height of the final building is 20 feet.

Find out more on scaling at: brainly.com/question/25722260

7 0

1 year ago

Read 2 more answers

Please help with #12

ExtremeBDS [4]

Answer:

a. 1 1/8 b. 8/9

Step-by-step explanation:

You can set this up as a proportion to solve. For part a. we know that 2/3 of the road is 3/4 mile long. 2/3 + 1/3 = the whole road, so we need how many miles of the road is 1/3 its length. Set up the proportion like this:

$\frac{\frac{2}{3} }{\frac{3}{4} } =\frac{\frac{1}{3} }{x}$

Cross multiplying gives you:

$\frac{2}{3}x=\frac{1}{3}*\frac{3}{4}$

The 3's on the right cancel out nicely, leaving you with

$\frac{2}{3}x=\frac{1}{4}$

To solve for x, multiply both sides by 3/2:

$\frac{3}{2}*\frac{2}{3}x=\frac{1}{4}*\frac{3}{2}$ gives you

$x=\frac{3}{8}$

That means that the road is still missing 3/8 of a mile til it's finished. The length of the road is found by adding the 3/4 to the 3/8:

$\frac{3}{4}+\frac{3}{8}=\frac{6}{8}+\frac{3}{8}=\frac{9}{8}$

So the road is a total of 1 1/8 miles long.

For b. we need to find out how much of 1 1/8 is 1 mile:

1 mile = x * 9/8 and

x = 8/9. When 1 mile of the road is completed, that is 8/9 of the total length of the road completed.

8 0

3 years ago