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Ganezh [65]
3 years ago
12

What is four hundred twenty-eight and forty-six hundredths written in standard form? 5th grade

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

4.2846*10^2

Step-by-step explanation:

428.46

4.2846*10^2 hopefully

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_16. Which expression is equivalent to
Phantasy [73]

Answer:

-2x-8

Step-by-step explanation:

1) Distribute:

-6/3x+-15/3-3

2) Simplify:

-2x-5-3

3) combine like terms:

-2x-8

hope this helps

5 0
3 years ago
CAN SOMEONE HELP ME!<br>​
Georgia [21]

Answer:

26

Step-by-step explanation:

5 × 4 = 20 (rectangle)

8-5 = 3 (triangle)

3×4÷2 = 6

20+6 = 26

4 0
2 years ago
you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0
1 year ago
A little help here ^-^
frosja888 [35]
252 is the answer because you can square of every small box to each parts area then add it up
8 0
3 years ago
Read 2 more answers
Could anyone help me on this please
kozerog [31]

Answer:

yes? what is the question?

Step-by-step explanation:

8 0
3 years ago
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