3 years ago

A triangle ABC with vertices A(6,8) B(6,12) C(10,12) is rotated to 180. What are the coordinates of B

1 answer:

8 0

Assuming rotation is about origin, then
R180: (x,y)->(-x,-y)

So
A(6,8)->A'(-6,-8)
B(6,12)->B'(-6,-12)
C(10,12)->C'(-10,-12)

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Alex777 [14]

Answer:

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Step-by-step explanation:

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3 years ago

T is the midpoint of KL. K has coordinates (2,−6), and T has coordinates (−4,2). Identify the coordinates of L.

kotykmax [81]

Answer:

$L = (-10,10)$

Step-by-step explanation:

Given

$K = (2,-6)$

$T = (-4,2)$

Required

Determine the coordinates of L

Since T is the midpoint of K and L, we make use of:

$T_x = \frac{K_x + L_x}{2}$

and

$T_y = \frac{K_y + L_y}{2}$

Solving for $L_x$

$T_x = \frac{K_x + L_x}{2}$

$-4 = \frac{2 + L_x}{2}$

Multiply through by 2

$-8 = 2 + L_x$

$L_x = -8 - 2$

$L_x = -10$

Solving for $L_y$

$T_y = \frac{K_y + L_y}{2}$

$2 = \frac{-6+L_y}{2}$

Multiply through by 2

$4 = -6 + L_y$

$L_y = 4 + 6$

$L_y = 10$

Hence: The coordinates of L is:

$L = (-10,10)$

6 0

3 years ago

4x – 8 Please helppp

Nadya [2.5K]

-2

Divide each term (-4x = 8 by -4)

Cancel the common factor of -4

x = 8/-4

THEN DIVIDE

x=-2

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2 years ago

Solve by taking the square root of both sides. 3(x+4)^2-24=0

VARVARA [1.3K]

3(x+4)^2-24=0

3(x+4)^2 = 24

(x+4)^2 = 24/3

(x+4)^2 = 8

(x+4)² = (2√2)² ⇒ x+4 = 2√2 ⇒ x = 2√2 - 4

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ELEN [110]

X= the amount of money he can spend

x=$20

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3 years ago

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