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tino4ka555 [31]
3 years ago
7

You purchase 26 parking hours that you can use the next month to park your food truck at the fair. Weekday hours park $2 per hou

r and weekend hours cost $10 per hour. You spend a total of $220. How many week day hours did you purchase.
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0

Answer:

Number of week day hours purchased  is 5

Step-by-step explanation:

Total number of Parking hours purchased = 26 parking hours

Parking cost on weekdays = $2 per hour

Parking costs on weekends = $10 per hour

Total amount spent on parking =  $220.

To Find:

Number of week days purchased = ?

Solution:

Let  

The number of week days purchased be x

The number of weekends purchased be  y

We know that the total hours purchased is 26

So,

x+y = 26

y = 26-x------------------------------------------------------(1)

Now the total cost is 220

(Total number of weekdays X cost per weekday ) +(Total number of weekends + cost per weekend) =220

Substituting the values

=>x\times 2 + y \times 10 = 220

=>x \times 2 + (26-x) \times 10 =220

=>2x + 260 -10x =220

=>260 -8x = 220

=>260 -220 =8x

=>40 = 8x

=>x=\frac{40}{8}

x= 5-------------------------------------------(2)

Now substituting (2) in (1) we get

y= 26-5

y= 21

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Step-by-step explanation:

Simplifying

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Joe owns a stock which has probability .5 of going up. This morning, he bought a ticket in a lottery game which gives him a prob
Anit [1.1K]

Answer:

The probability that Joe's stock will go up and he will win in the lottery  is 0.00005.

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Given:

P (X) = 0.50

P (Y) = 0.0001

The events of the stock going up is not dependent on the the event of Joe winning the lottery.

So the events <em>X</em> and <em>Y</em> are independent of each other.

Independent events are those events that can occur together at the same time.

The joint probability of two independent events <em>A</em> and <em>B </em>is,

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Based on your value of x in question #1, what is the value for ∠EHF
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Answer:

∠EHF = 132°

Step-by-step explanation:

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=====================

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Then ∠EHF :

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