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liubo4ka [24]
3 years ago
9

Alr help me on this one.

Mathematics
1 answer:
tatyana61 [14]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

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(-0.25x -8)-(5.5x + 9.4) the simplified expression
Alja [10]

Answer:

=−5.75x−17.4

Step-by-step explanation:

=−0.25x−8+−1(5.5x+9.4)

=−0.25x+−8+−1(5.5x)+(−1)(9.4)

=−0.25x+−8+−5.5x+−9.4

another way >>>><<<<

=−0.25x+−8+−5.5x+−9.4

=(−0.25x+−5.5x)+(−8+−9.4)

=−5.75x+−17.4

Answer:

=−5.75x−17.4

3 0
3 years ago
Natasha was thinking of a number.
skelet666 [1.2K]

Answer:

28.1

Step-by-step explanation:

You can answer questions like this by working backwards.

To do this we can divide 78.2 by 2 and that gets us 39.1

Now we have to subtract 11 from it and that gets us our final answer:

28.1

8 0
2 years ago
Read 2 more answers
Kelly bought a new car for $20,000. The car depreciates at a rate of 10% per year.
Vlad1618 [11]

Answer:

Use the formula.

P=P'(1-R/100)^T

where,

P=final rate

P'=initial rate

R=Rate of Depreciation

T=Time.

3 0
3 years ago
When Noah goes bowling, his scores are normally distributed with a mean of 150 and a standard deviation of 12. What is the proba
Zarrin [17]

Answer:

The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)

Step-by-step explanation:

Given that:

Mean = μ = 150

SD = σ = 12

Let x1 be the first data point and x2 the second data point

We have to find the z-scores for both data points

x1 = 135

x2 = 167

So,

z_1 = \frac{x_1-mean}{SD}\\= \frac{135-150}{12}\\=\frac{-15}{12}\\=-1.25

And

z_2 = \frac{x_2-mean}{SD}\\z_2 =\frac{167-150}{12}\\=\frac{17}{12}\\= {1.416}

We have to find area to the left of both points then their difference to find the probability.

So,

Area to the left of z1 = 0.1056

Area to the left of z2 = 0.9207

Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151

Hence,

The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)

3 0
3 years ago
Maths gcse please help me
rosijanka [135]
Im sorry wish i could help but the equation is a little confusing give me a few moments and i will figure out the answer okay?
3 0
3 years ago
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