Answer:
2 non real solutions.
Step-by-step explanation:
We need to use discriminant,
for ax²+bx+c=0
The discriminat is b²-4ac
If the discriminant is,
→ less than 0, then 0 real solutions
→ equal to 0, then 1 real solutions
→ more than 0, then 2 real solutions
Given that,
7x²−4x+3=0
a=7, b=-4, and c=3
→ (-4)²-4(7)(3)
→ 16-84
→ -68
You can see this is less than 0, then non real solutions. [2 nonreal solutions]
Answer:
DNE
Step-by-step explanation:
The the given table, we have;
As x approaches -14 from the left, at x = -14.001, p(x) = 1.96
As x approaches -14 from the right, at x = -13.999, p(x) = 1.97
The value of p(x) when x = -14 is 
= Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;
Does Not Exist, DNE.
is this a school qustion? if not
cool me too
Answer:
ok
Step-by-step explanation:
Answer:
D. None of the choices are correct.
Step-by-step explanation:
If <em>B</em> is the midpoint of AC, then that means that AB is congruent to BC. Because this is true, you can set 8x + 4 and 10x - 8 equal.
8x + 4 = 10x - 8
Now just solve for x. Subtract 8x from both sides and add 8 to both sides.
4 = 2x - 8
12 = 2x
Then divide by 2.
6 = x
Another way to do this problem is to set up the same equation, but instead of solving it, plug in answer choices A, B, and C independently of each other. Then simplify to see if those are right. You'll find out that none of them are.
