The ODE is separable:

Integrating both sides gives

Answer:
374.123 m^2
rounded it would be 374.1 m^2
3x - 12
3(3x/3 - 12/3)
3(x - 4)
The answer is: 3(x - 4).
Answer:
The bounded area is 5 + 5/6 square units. (or 35/6 square units)
Step-by-step explanation:
Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)
Such that f(x) > g(x) in the given interval.
This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).
We want to find the area bounded by:
f(x) = y = x^2 + 1
g(x) = y = x
x = -1
x = 2
To find this area, we need to f(x) - g(x) between x = -1 and x = 2
This is:


We know that:



Then our integral is:

The right side is equal to:

The bounded area is 5 + 5/6 square units.
B I got this by graphing it into my graphing calculator. Hope this helps