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3 years ago

8

What is the halfway fraction between 3/5 and 7/10

1 answer:

Dmitry [639]3 years ago

7 0

The answer is 13/20. So 3/5 is equal to 6/10 so you're looking for the fraction that's half of 7/10 and 6/10 which is 6.5/10 but you can't use decimals in a fraction so you multiply both sides by 10 which would equal 65/100 and simply, and that would be 13/20.

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mel-nik [20]

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2 years ago

2.8 - 0.92 mathematics

kirill115 [55]

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2 years ago

Find the product. <br><br> (6a + b) 2

I am Lyosha [343]

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3 years ago

Johnny paid $19 for a pair of jeans. It was originally $33. What percent discount did he receive?

Ber [7]

Answer:

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4 0

3 years ago

Select True or False for each statement.

SSSSS [86.1K]

$\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32$

TRUE

$\sqrt[5]{36^4}=36^{4/5}$

which surely isn't 36. FALSE

$\sqrt{12} - \dfrac 2 5 \sqrt{75} = 2 \sqrt{3} -\dfrac 2 5 (5) \sqrt{3} = 0$

FALSE

For the fourth one we have a

$\sqrt{98b} + \sqrt{2b}$

which isnt

$10\sqrt{b}$

so this is FALSE.

$\dfrac{1}{(\sqrt 5 - \sqrt 6)^2}$

$= \dfrac{1}{(\sqrt 5 - \sqrt 6)^2} \cdot \dfrac{(\sqrt 5 + \sqrt 6)^2}{(\sqrt 5 + \sqrt 6)^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{ ( (\sqrt 5 - \sqrt 6)(\sqrt 5 + \sqrt 6))^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{( 5-6)^2}$

$=(\sqrt 5 + \sqrt 6)^2$

No fractions in that one so FALSE.

3 0

2 years ago