14a^2bc^4/21abc^6 = 2a/3b^2
1: 40%
2: 30%
3: 20%
If we know one of the succeeded, then
1: 44.44%
2: 33.33%
3: 22.22%
If under the circumstance that they all fail to meet a strong leader, the board picks one of them at random,
1: 43.33%
2: 33.33%
3: 23.33%
The first person has a 2 in 5 chance of randomly getting a strong leader. If the first person doesn't find a strong leader, the second person has a 2/4 chance of getting a strong leader. If neither the first nor second person gets a strong leader, the third sales person has a 2/3 chance of getting a strong leader.
1: 2/5=40% Chance
2: (3/5)*(2/4)=30% Chance You have to take the probability the first rep failed to get a strong leader, then multiply by the probability the second rep gets a strong leader.
3: (3/5)*(2/4)*(2/3)=20% You have to take the probability both the other people failed, then multiply by the probability they succeeded.
Answer:
Step-by-step explanation:
-5 + (8 x -7)
using PEMDAS, (8 x -7) = -56
so -5 + -56 = -61
1/5 is an expression that represents 1÷5= .2
Since the return decimal equivalent doesn't go on forever and has a finite end, this is a member of the rational number set.
Answer:
$20.60
Step-by-step explanation:
25.75x20%=5.15
25.75-5.15=20.60
