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Umnica [9.8K]
3 years ago
10

Again the auction house raffle sold 200 tickets at $1 each. How many prizes of $10 should they to make the raffle a fair game?

Mathematics
2 answers:
jekas [21]3 years ago
5 0
200; $1e\pp

they should sell 20 prizes

20x10=200
stiv31 [10]3 years ago
5 0
200 tickets at $1.00 each =$200 so 200 Divided by $10 is 20... The answer is 20 prizes forc$10
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3 0
4 years ago
The standard form of the equation of a parabola is y= x2 - 6x + 14.
Bas_tet [7]
<h3><u>Option C</u></h3><h3><u>The vertex form of the equation is:</u></h3>

y = (x - 3)^2 + 5

<em><u>Solution:</u></em>

<em><u>The vertex form of equation is given as:</u></em>

y = a(x- h)^2 + k

Where, (h, k) is the vertex

Given that,

y = x^2 - 6x + 14

We have to find the vertex form of equation

Step 1:

Complete the square for x^2 - 6x + 14

\text{ Use the form } ax^2 + bx + c \text{ to find values of a, b, c }

a = 1

b = -6

c = 14

Consider the vertex form of a parabola.

a(x + d)^2 + e ----- eqn 1

Substitute the values of  a and b into following:

d = \frac{b}{2a}\\\\d = \frac{-6}{2 \times 1}\\\\d = -3

Find the value of "e" using following formula:

e = c - \frac{b^2}{4a}\\\\e = 14 - \frac{(-6)^2 }{4 \times 1}\\\\e = 14 - 9\\\\e = 5

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Thus vertex form form is found. Option C is correct

3 0
3 years ago
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