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Natali [406]
3 years ago
8

A rectangular page is designed to contain 81 square inches of print. The margins at the top and bottom of the page are each 1 in

ch deep. The margins on each side are 1½ inches wide. What should the dimensions of the page be so that the least amount of paper is used?
Social Studies
1 answer:
Nookie1986 [14]3 years ago
8 0

Answer:

x = 11.02 inch by  y = 7.35 inch

Explanation:

Let the width of the print be = x

Then the width of the page is x + (1.5+1.5) = x + 3

Let the height of the print be = y

Then the height of the page is y + (1+1) = y + 2

Given the area of the print is 81 square inches

That means, xy = 81

Therefore, y = \frac{81}{x}

Therefore, the area of the page is

A = (x + 3)(y + 2)

   = (x + 3)(\frac{81}{x} + 2)

Now for least amount of paper to be used,

\frac{dA}{dx}=(x+3)(\frac{81}{x}+2)

\frac{dA}{dx}= \left (\frac{81}{x}+2  \right )+\left ( x+3 \right )\left ( -\frac{81}{x^{2}} \right )=0

\frac{81+2x}{x}=\frac{(x+3)(81)}{x^{2}}

81x+2x^{2}=81x+81\times 3

2x^{2}=243

x = 11.02 inch

Now y = \frac{81}{x}

          = \frac{81}{11.02}

          = 7.35 inch

Therefore the dimensions of thr page for the least amount of paper is x = 11.02 inch by  y = 7.35 inch

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