Hey there !
Molecular Weight: 262.86 g/mol
Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L
Number of moles of solution :
number of moles = volume x molarity
number of moles = 1 x 0.3 => 0.3 moles
Therefore:
1 mole Mg₃(PO₄)₂ ------------------- 262.86 g
0.3 moles ----------------------------- mass of Mg₃(PO₄)₂ ??
mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1
mass of Mg(PO₄)₂ => 78.858 g
Hope this helps!
Answer:
The volume of container is <em>39.14 L.</em>
Explanation:
Given data:
Number of moles of neon = 4.0 mol
Pressure of gas = 2.5 atm
Temperature of gas = 25°C
Volume of container = ?
Solution:
we will use general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273 = 298 K
Now we will put the values in formula.
2.5 atm × V = 4.0 mol × 0.0821 atm.L/ mol.K × 298 K
V = 97.86 atm.L /2.5 atm
V = 39.14 L
The volume of container is 39.14 L.
Love the toradora pfp, also the answer to your question is...
answer: from newtons second law of motion,
F=ma hence,
F=20N
m=5kg so,
20=5×a
a=4m/s^2
Where’s the questions hun? I don’t even see the questions you need answered
