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3 years ago

What mass of solute should you measure out in order to make 1,000 mL of a 0.3 M solution of magnesium phosphate Mg3(PO4)2?

Chemistry

1 answer:

vivado [14]3 years ago

7 0

Hey there !

Molecular Weight: 262.86 g/mol

Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L

Number of moles of solution :

number of moles = volume x molarity

number of moles = 1 x 0.3 => 0.3 moles

Therefore:

1 mole Mg₃(PO₄)₂ ------------------- 262.86 g

0.3 moles ----------------------------- mass of Mg₃(PO₄)₂ ??

mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1

mass of Mg(PO₄)₂ => 78.858 g

Hope this helps!

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AveGali [126]

Answer:

from the pic:

$empirical \: formular : \: \: C _{2}H _{3}O _{2}$

since molar mass is 118.084 g/mol;

$(C _{2}H _{3}O _{2}) _{n} = 118.084 \\ C _{2n}H _{3n}O _{2n} = 118.084 \\(12 \times 2) _{n} + (1 \times 3) _{n} + (16 \times2 ) _{n} = 118.084 \\ 24_{n} + 3_{n} + 32_{n} = 118.084 \\ 59_{n} = 118.084 \\ n = 2$

${ \boxed{ \bf{molecular \: formular : \: C _{4}H _{6}O _{4}}}}$

It is an aldehyde with structure ( second pic )

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3 years ago

Ketones undergo a reduction when treated with sodium borohydride, NaBH4. The product of the above reaction has the following spe

Anna71 [15]

Answer:

The product is cyclohexanol

Explanation:

Firstly,

A ketone undergo a borohydride reduction reaction to form an alcohol as below,

R-CO-R' ⇒ R-CO(OH)-R'

IR Spectrum confirms that alcohol group is existed with the peak at 3400 cm⁻¹
From 1H-NMR, the product has 10 hydrogen atoms, the MS suggest that the formula is C₅H₁₀O (M = 86). With this formula, the alcohol is monosaturated. Since, the substance already underwent reduction reaction, the only way to suggest a monosaturated compound is a cyclic alcohol. So the compound is cyclopentanol.
Check with other spectroscopic properties,

3 signals of 13C NMR confirms the structure is symmetrical, δ 24.2, (-CH₂-CH₂-CH(CH₂-)-OH), δ 35.5 (-CH₂-CH₂-CH(CH₂-)-OH), δ 73.3 (-CH₂-CH₂-CH(CH₂-)-OH).

1H NMR confirms,

1.56 δ (4H, triplet) - (-CH₂-CH₂-CH-OH) ; triplet as coupling with 2 H,

1.78 δ (4H, multiplet) - (-CH₂-CH₂-CH-OH); multiplet as coupling with 2H of CH₂, 1 H of CH

3.24 δ (1H, quintet); - (-CH₂-CH₂-CH(CH₂-)-OH), coupling with4 H of 2 group of CH₂

3.58 δ (1H, singlet); - (-CH₂-CH₂-CH(CH₂-)-OH), hydrogen of alcohol group, not tend to coupling with other hydrogen

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3 years ago

Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II) chloride.

Marrrta [24]

$2Cr + 3CoCl_2$ → $2CrCl_3 + 3Co$

Explanation:

The products formed are chromic chloride and cobalt.

Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt

Type of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.

Reactants used in the reaction are -

Chromium $(Cr)$

Cobaltous Chloride $(CoCl_2)$

Products formed in the reaction are -

Chromic Chloride $(CrCl_3)$

Cobalt $(Co)$

Hence, the chemical reaction is as follows -

$Cr + CoCl_2$ → $CrCl_3 + Co$

For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.

Hence, the balanced equation is -

$2Cr + 3CoCl_2$ → $2CrCl_3 + 3Co$

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4 years ago

The substances present before a chemical reaction takes place are called?

andrew11 [14]

The substances present before the reaction are the reactants. (As the reaction goes through, the substances that are produced are called the products of the reaction).

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3 years ago

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Marat540 [252]

Answer:

ooh sorry, but will this help you now:

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Explanation:

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3 years ago