The answer is light years
The question is incomplete, the complete question is;
Zinc and sulfur react to form zinc sulfide by the equation shown below. How many grams of ZnS can be formed when 12.0 g of Zn reacts with 6.50 g of S? (Atomic mass: Zn = 65.38, S = 32.06).
Answer:
17.5 g of ZNS
Explanation:
The equation of the reaction is;
Zn(s) + S(s) ------->ZnS(s)
Number of moles of Zn = 12.0/65.38 = 0.18 moles
Number of moles of S = 6.50/32.06 = 0.20 moles
Hence Zn is the limiting reactant
If 1 mole of Zn yields 1 mole of ZnS
Then 0.18 moles of Zn also yields 0.18 moles of ZnS
Mass of ZnS produced = 0.18 moles * 97.44 g/mol = 17.5 g of ZNS
According to the image in this question, the type of reaction shown is that of fission because nuclei are being split into smaller and smaller places.
<h3>What is nuclear fission?</h3>
Nuclear fission in radioactivity is the process whereby the nuclei of atoms split into smaller particles.
In the above diagram, an atom of uranium is labeled and its nucleus is shown to split into smaller particles in succession.
Therefore, the reaction exemplifies a nuclear fission because nuclei are being split into smaller and smaller places.
Learn more about fission at: brainly.com/question/2732120
Answer:
The molecular formula of this compound is 
Explanation:
From the given,
Mass of compound = 7.36 g
Molar mass of compound = 34.0 g/mol
The mass of oxygen = 6.93 g
The hydrocarbon contains only hydrogen and carbon.
Mass of hydrogen + Mass of oxygen = 7.36 g
Mass of hydrogen + 6.93 g = 7.36 g
Mass of hydrogen = 7.36 - 6.93 = 0.43g
Molar mass of hydrogen = 1.0 g/mol
Molar mass of oxygen = 16 g/mol
Now divided each one by 0.43
Oxygen:
Hydrogen :
