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Hunter-Best [27]
3 years ago
9

The value of an investment increased from 750 to 795 by which percentage did the value of the investment increase

Mathematics
1 answer:
kupik [55]3 years ago
7 0
So what you do is take the old value - the new value/the old value so the equation is 795 - 750 / 750 so the answer is 6%
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traingle ABC has been dilated aboit point A by a scale factor of 1/3. What are the lengths, in units, of the three sides of tria
solniwko [45]

Answer:

You need to show the graph so i can see numbers, you cant dilate the traingle without knowing where it is on the graph.

Step-by-step explanation:

4 0
3 years ago
.
Maksim231197 [3]

Answer:

D. x=1

Step-by-step explanation:

Image can be rewritten as 3x + 6 = 9.

Solve for x.

3x +6 = 9

Isolate x by subtracting 6 from both sides.

3x = 3

Get rid of the 3 by dividing by 3 on both sides.

x = 1

Hope this helped.

8 0
2 years ago
There are a total of 18 frocks. If the ratio of purple frocks to white frocks is 2 to 4, how many of them are white?
Oksana_A [137]
I think it will be 2:4. 2X9=18 so u × 4×9=36 so its 18 to 36
7 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
Bo bought a few items for $93.84, not including tax. If the tax rate was 7%, what was the total cost of these items, including t
notsponge [240]

Answer:

Total cost is $100.41 ( $93.84 + $6.57)

Step-by-step explanation:

Thinking Point: The total cost is the cost of the items PLUS the tax. 93.84 ∙ 0.07 = 6.5688 (round to “cents”) = $6.57


Hope this helped!

4 0
3 years ago
Read 2 more answers
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