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inna [77]
3 years ago
14

Write a even number between 3 and 12. Draw a picture and then write a sentence to explain why it is an even number

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0
Even numbers are 2 4
rewona [7]3 years ago
3 0
6, 6 is an even number because it can be divided by two and has always two same numbers such as 3 that combine to make that even number such as 3+3 

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2d + 1 = 9<br><br> so d = what
weeeeeb [17]

Answer:

d is 4 :))

hope that helped

8 0
3 years ago
Read 2 more answers
If the volume of the bat is 82
Assoli18 [71]

The volume that is left to be filled is approximately: 3,332.6 in.³

<h3>What is the Volume of a Box?</h3>

Volume of a box = (length)(width)(height)

Given the following:

Volume of the bat = 82 cubic in.

Length of box = 30 in.

Width = 18.97 in.

Height = 6 in.

The remaining volume to be filled = volume of box - volume of bat

= (30)(18.97)(6) - 82

= 3,332.6 in.³

Learn more about the volume of a box on:

brainly.com/question/14957364

#SPJ1

4 0
2 years ago
Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per
Dima020 [189]

Answer:

S \leq 200

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

SMS = 16.95 + 0.05S

For Awesome Wireless, we have:

SMS = 22.95 + 0.02S

For Awesome Wireless is greater or equal to Phone R-Us, we have:

22.95 + 0.02S \geq 16.95 + 0.05S

Collect Like Terms

0.02S - 0.05S \geq 16.95 - 22.95

-0.03S \geq -6

Solve for S

\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}

S \leq 200

<em>Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200</em>

4 0
3 years ago
PLZ HELP
belka [17]

Answer:

425261625

Step-by-step explanation:

1+2-4252+425251-34%+5%

4 0
3 years ago
A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc
aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0
3 years ago
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