Line k has a slope of - 1/6. What is the slope of a line that is perpendicular to like k?
1 answer:
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y=3x+6
Step-by-step explanation:
point 1 (2;12)
point 2 (4;18)
m=3
y=mx+b
sub in a point and gradient
12=3(2)+b
12=6+b
b=6
y=3x+6
Answer:
(x+2)² + (y-3)² = 26
The graphic is showed below
Step-by-step explanation:
The circle equation is given by the expression:
(x-a)² +(y-b)² = r²
The point (a,b) represents the center, and r is the radius. So:
(x+2)² + (y-3)² = r²
If the point A (3,2) is on the circle, then we can replace it in the equation to find r:
(3+2)² + (2-3)² = r²
r² = 5² + (-1)²
r² = 25 + 1
r² = 26
So, the circle has radius r = √26, and the equation is:
(x+2)² + (y-3)² = 26
To graph it, we must put the center C(-2,3), then the radius r = √26 and form a circle, like the figure below.
