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3 years ago

Line k has a slope of - 1/6. What is the slope of a line that is perpendicular to like k?

1 answer:

6 0

The slope of a line and the perpendiular line that intercept will always have a product of -1

If the slope k=-1/6, the perperndicular line can be found by finding the product of the slope and -1

-1= (slope)(perpendicular line slope)
perpendicular line slope= slope(-1)
= -1/6(-1)
= 6

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2 years ago

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3 years ago

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Andrew [12]

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So;

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Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

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1 year ago

I need some help, please. 25 points. : )

Svetlanka [38]

the awnser is -6

im very sure let me know if im wrong.

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2 years ago