![\bf \begin{array}{ccll} x&y\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&30\\ 2&35\\ 3&40\\ 4&45\\ a&5(a)+25 \end{array}\qquad \qquad y=5x+25](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%0Ax%26y%5C%5C%0A%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%26%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%5C%5C%0A1%2630%5C%5C%0A2%2635%5C%5C%0A3%2640%5C%5C%0A4%2645%5C%5C%0Aa%265%28a%29%2B25%0A%5Cend%7Barray%7D%5Cqquad%20%5Cqquad%20y%3D5x%2B25)
if you have already covered slopes, you could also get it that way, in fact is simpler that way.
8.40/3 = £2.80 each
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<span>f = v + at
Subtract v from both sides.
f - v = at
Divide both sides by a.
(f - v)/a = t
Switch sides.
t = (f - v)/a
![t = \dfrac{f - v}{a}](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cdfrac%7Bf%20-%20v%7D%7Ba%7D%20)
</span>
5x - 2 = 13
5x = 13 + 2
5x = 15 (divide both sides by 5 to get x)
5x/5 = 15/5
x = 3
Start at -4 and go to the right 6 times on the number line and you should end up with 2