Answer:
x2- 2x+1 =x2-x-x+1
=x(x-1) -1(x-1)
=(x-1)(x-1)
We need to keep it this way as this is the simplest way of expressing its factors.
-1
We have that
(w^5*z^2)*(-9*w^2*z^<span><span>5)</span>
</span><span>Multiplying exponential expressions
we know that
</span>w^5<span> multiplied by </span>w^<span>2 = w</span>^<span>(5 + 2) = w</span>^7
and
z^2<span> multiplied by </span>z^<span>5 = z</span>^<span>(2 + 5) = z</span>^7
therefore
(w^5*z^2)*(-9*w^2*z^5) =-9*( w^7)*( z^7)
-9*( w^7)*( z^7)=-(3^2)*( w^7)*( z^7)
the answer is
-(3^2)*( w^7)*( z^7
To move tot he right h units, subtract h from every x
to move up k units, add k to the whole equaiton
added 1 to every x (subtract -1)
added6 to whole thing
moved -1 to right (moved 1 to left)
moved up 6 units
answer is A
Answer:
yes
Step-by-step explanation:
Answer:
Last one
Step-by-step explanation:
