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3 years ago

8

Find the area of the composite figure. Please help me

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

51.5 ft^2

Step-by-step explanation:

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A tailor used 2 meters of string to make 10 Halloween masks. He used ___ of a meter for each mask.

Lostsunrise [7]

2 meters were used in 10 masks

2meters/10masks= 0.2meters per mask

5 0

3 years ago

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Answer this volume based Question. I will make uh brainliest + 50 points

Harlamova29_29 [7]

Answer:

$\huge{\purple {r= 2\times\sqrt[3]3}}$

$\huge 2\times \sqrt [3]3 = 2.88$

Step-by-step explanation:

For solid iron sphere:
radius (r) = 2 cm (Given)

Formula for $V_{sphere}$ is given as:

$V_{sphere} =\frac{4}{3}\pi r^3$

$\implies V_{sphere} =\frac{4}{3}\pi (2)^3$

$\implies V_{sphere} =\frac{32}{3}\pi \:cm^3$

For cone:
r : h = 3 : 4 (Given)
Let r = 3x & h = 4x

Formula for $V_{cone}$ is given as:

$V_{cone} =\frac{1}{3}\pi r^2h$

$\implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)$

$\implies V_{cone} =\frac{1}{3}\pi (36x^3)$

$\implies V_{cone} =12\pi x^3\: cm^3$

It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
$\implies V_{cone} = V_{sphere}$

$\implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}$

$\implies 12x^3= \frac{32}{3}$

$\implies x^3= \frac{32}{36}$

$\implies x^3= \frac{8}{9}$

$\implies x= \sqrt[3]{\frac{8}{3^2}}$

$\implies x={\frac{2}{ \sqrt[3]{3^2}}}$

$\because r = 3x$

$\implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}$

$\implies r=3\times 2(3)^{-\frac{2}{3}}$

$\implies r= 2\times (3)^{1-\frac{2}{3}}$

$\implies r= 2\times (3)^{\frac{1}{3}}$

$\implies \huge{\purple {r= 2\times\sqrt[3]3}}$
Assuming log on both sides, we find:

$log r = log (2\times \sqrt [3]3)$

$log r = log (2\times 3^{\frac{1}{3}})$

$log r = log 2+ log 3^{\frac{1}{3}}$

$log r = log 2+ \frac{1}{3}log 3$

$log r = 0.4600704139$

Taking antilog on both sides, we find:

$antilog(log r )= antilog(0.4600704139)$

$\implies r = 2.8844991406$

$\implies \huge \red{r = 2.88\: cm}$

$\implies 2\times \sqrt [3]3 = 2.88$

8 0

2 years ago

Let g(x)=x-3 and h(x)=x^2+6 find (h o g) (1)

cupoosta [38]

$g(x)=x-3 \ \ \ and\ \ \ h(x)=x^2+6 \\\\(h \circ g) (1)=h\bigg (g(1)\bigg)=h\bigg(1-3\bigg)=h(-2)=(-2)^2+6=4+6=10$

5 0

3 years ago

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Hi again, need help on this please, This is for my End-Of-Year Test, help!

allsm [11]

The correct answer is the first one.

5 x 100 is correct.
9 x 1 is correct because the 9 is in the ones section, not the tens.
3 x 1/10 is correct because it is equal to 0.3.
7 x 1/1000 is correct because it is equal to 0.007.

Hope this helped! You’re welcome

4 0

3 years ago

The vertices of ΔGHI are G(-3,0), H(-5,-5), and I(1,-5). What are the coordinates of the image after being reflected over the y-

s2008m [1.1K]

After reflecting the points of triangle GHI over the y axis, the new points will be:
G' (3,0)
H' (5,-5)
I' (-1,-5)

6 0

3 years ago