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Xelga [282]
3 years ago
10

Explain how to find the least common multiple of 8 and 10

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

40

Step-by-step explanation:

<em>divide</em><em> </em><em>eight</em><em> </em><em>and</em><em> </em><em>ten</em>

<em>use</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>that </em><em>can</em><em> </em><em>divide</em>

<em>use</em><em> </em><em>two</em>

<em>making</em><em> </em><em>four</em><em> </em><em>and</em><em> </em><em>five</em>

<em>use</em><em> </em><em>two</em><em> </em><em>again</em>

<em>making</em><em> </em><em>two</em><em> </em><em>and</em><em> </em><em>five</em>

<em>use</em><em> </em><em>two</em><em> </em><em>again</em>

<em>making </em><em>one</em><em> </em><em>and</em><em> </em><em>five</em>

<em>now</em><em> </em><em>we</em><em> </em><em>use</em><em> </em><em>five</em>

<em>making</em><em> </em><em>one</em><em> </em><em>and </em><em>one</em>

<em>that</em><em> </em><em>is</em>

<em>two</em><em> </em><em>times</em><em>.</em><em>t</em><em>w</em><em>o</em><em> </em><em>times</em><em> </em><em>two</em><em> </em><em>times</em><em> </em><em>five</em><em> </em><em>w</em>

<em>which</em><em> </em><em>is</em><em> </em><em>eight</em><em> </em><em>times</em><em> </em><em>five</em>

<em>which</em><em> </em><em>is</em><em> </em><em>fourty</em>

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Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
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Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

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Ana angle measure 79.8 degrees less than the measure of it’s complementary angle what is the measure of each angle
RUDIKE [14]

Answer:

x = 129.8 degrees,  y = 50.2 degrees,    x + y = 180

Step-by-step explanation:

Let's say you have 2 supplementary angles, x and y

So x + y = 180

if x is 79.8 degrees less than the measure of a supplementary angle, then x = y - 79.8

Putting this into our x + y = 180 equation, we get

(y - 79.8) + y = 180

2y - 79.8 = 180

2y = 180 + 79.8

2y = 259.8

y = 259.8/2 = 129.9 degrees.

so x = 129.9 - 79.6 = 50.3 degrees.

See if it worked. x = 129.9 degrees,  y = 50.3 degrees,    x + y = 180 so we found the correct two angles! :-)

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