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Xelga [282]
3 years ago
10

Explain how to find the least common multiple of 8 and 10

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

40

Step-by-step explanation:

<em>divide</em><em> </em><em>eight</em><em> </em><em>and</em><em> </em><em>ten</em>

<em>use</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>that </em><em>can</em><em> </em><em>divide</em>

<em>use</em><em> </em><em>two</em>

<em>making</em><em> </em><em>four</em><em> </em><em>and</em><em> </em><em>five</em>

<em>use</em><em> </em><em>two</em><em> </em><em>again</em>

<em>making</em><em> </em><em>two</em><em> </em><em>and</em><em> </em><em>five</em>

<em>use</em><em> </em><em>two</em><em> </em><em>again</em>

<em>making </em><em>one</em><em> </em><em>and</em><em> </em><em>five</em>

<em>now</em><em> </em><em>we</em><em> </em><em>use</em><em> </em><em>five</em>

<em>making</em><em> </em><em>one</em><em> </em><em>and </em><em>one</em>

<em>that</em><em> </em><em>is</em>

<em>two</em><em> </em><em>times</em><em>.</em><em>t</em><em>w</em><em>o</em><em> </em><em>times</em><em> </em><em>two</em><em> </em><em>times</em><em> </em><em>five</em><em> </em><em>w</em>

<em>which</em><em> </em><em>is</em><em> </em><em>eight</em><em> </em><em>times</em><em> </em><em>five</em>

<em>which</em><em> </em><em>is</em><em> </em><em>fourty</em>

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The vertical height v, in feet, of a snowboarder jumping off of an overhang can be modeled by the function h(t)=15-10t-16t^2, wh
olga55 [171]
I don't know for sure, but I think there might be an error in the way you copied your function. In all of my dealings with these types of problems, I have learned the formula to be h(t) = 15 + 10t - 16t^2. Notice the plus in front of the "10t". This is due to the fact that if he pushes off of the overhang he would have an upward force of 10 feet per second as soon as his feet left the ground. The only thing pulling him back to Earth is gravity, modeled by the "-16t^2". This is derived from a bit of slightly advanced physics involving the gravitational constant, but let's work under my formula for a second...

Either way, we will wind up using the Quadratic Formula (or possibly factoring if the numbers are easy enough to work with). So let's start. 

h(t)= 15 +10t - 16t^2

In order to use the QF or factoring I will need to make h(t)=0. Simply done by:

0= 15 +10t -16t^2

Looking at the numbers, I'd prefer to use the QF so here it is:

x= \frac{-b + or -  \sqrt{b^{2}-4ac } }{2a}

I know that my answer will need to be positive since you can't have a negative value when dealing with time, so I will eliminate the positive sign from the "+or-" part leaving me with:

x= \frac{-b -\sqrt{b^{2}-4ac } }{2a}

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There's a decent amount of math that would be difficult and sloppy for me to do over the computer, but all you need to do is solve the rest of the equation and you would get your answer.

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Answer:

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Step-by-step explanation:

<u>The billiard cue is 15 cm away from the table</u>

  • This refers to coordinates of (15, 0)

<u>The billiard cue touches the table at a point 60 cm off the ground</u>

  • This refers to coordinates of (0, 60)

<u>The slope is as per slope formula;</u>

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Answer:

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Step-by-step explanation:

The formula for the volume of a cone of radius r and height h is ...

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Then r² can be found in terms of h and V as ...

  r² = 3V/(πh)

The lateral surface area of the cone is ...

  A = (1/2)(2πr)√(r² +h²) = πr√(r² +h²)

The square of the area is ...

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Substituting for r² using the expression above, we have ...

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The corresponding value of r is ...

  r = √(3V/(πh)) = 9/√(π·h) ≈ 2.6319242

The optimal radius is 2.632 cm; the optimal height is 3.722 cm.

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The second derivative test applied to T finds that T is always concave upward, so the value we found is a minimum.

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Interestingly, the ratio of h to r is √2.

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Step-by-step explanation:

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