2 years ago

Can somebody help me with this problem

Mathematics

1 answer:

velikii [3]2 years ago

7 0

Friend i'm guessing its the second answer
Just an educated guess

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Free points: this is because of all the kindness I have seen on brainly:

VashaNatasha [74]

The answer is 35450 :)

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3 years ago

Read 2 more answers

WHOEVER IS RIGHT GETS BRAINLIST

pochemuha

The answer to the first question is b
I don’t know the answer to the second one sorry

4 0

2 years ago

A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa

tatuchka [14]

Answer:

Second puck travels farther

Step-by-step explanation:

Maximum height of first puck = 3 feet

The height of a second hockey puck is modeled by:

$y=x\left(0.15-0.001x\right)$

$y=0.15x-0.001x^2$

To find maximum height of second puck

$y'=0.15-0.002x$

Equate the derivative equals to 0

0.15-0.002x=0

$\frac{0.15}{0.002}=x$

75 = x

At x = 75

$y=0.15(75)-0.001(75)^2=5.625$

So, The maximum height of second puck is greater than first puck

So, Second puck travels farther

5 0

3 years ago

A salesperson at a jewelry store earns 8% commission each week. Last week, Ali sold $450 worth of jewelry. How much did Ali ma

Lilit [14]

Answer:

she earned 36$ and the store earned 409.5

Step-by-step explana

8% of 450

91% of 450

7 0

3 years ago

Solve for W <br> V = L + W

Elena L [17]

Answer:

W = -L + V

Step-by-step explanation:

V = L + W

~Subtract L to both sides

V - L = W

Best of Luck!

5 0

3 years ago