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Alborosie
3 years ago
8

In ΔPQR, what is sin Q written as a decimal?

Mathematics
2 answers:
UNO [17]3 years ago
8 0
Sin Q = oppo. / hypo
sin Q = 9/15
sin Q = 0.6
cricket20 [7]3 years ago
6 0
Hi there!

The sine of an angle is opposite over hypotenuse. Looking at angle Q, we know the opposite side is 9 and the hypotenuse is 15. These numbers give us this equation: sin Q = 9/15. Upon solving this equation, the result is approximately 56.5.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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Step-by-step explanation:

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In ΔABC, ∠B measures 35° and the values of a and b are 19 and 11, respectively. Find the remaining measurements of the triangle,
Anna35 [415]

Answer:

a)  ∠A = 82.2° , ∠C = 62.8° , c =   17.01

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i)</em></u>:-

Given data ∠B measures 35° and the values of a and b are 19 and 11

∠B = 35° and sides a = 19 and b = 11

<em>By using sine rule </em>

<em></em>\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{Sin C}  = 2 R<em></em>

now we will use

\frac{a}{sin A} = \frac{b}{sin B}

\frac{19}{sin A} = \frac{11}{sin 35}

cross multiplication , we get

\frac{19 X sin 35}{11} = sinA

<em>sin A = 0.990</em>

<em>A = sin⁻¹( 0.990) = 82.2°</em>

<em> ∠A = 82.2°</em>

<u><em>Step(ii):-</em></u>

we know that ∠A +∠B +∠C = 180°

                         ∠C = 180° - ∠A -∠B

                          ∠C = 180° -82.2°-35°

                          ∠C = 62.8°

<u><em>Step(iii)</em></u>:-

<em>we will use formula</em>

<em></em>\frac{b}{sin B} = \frac{c}{Sin C}<em></em>

<em></em>\frac{11}{sin 35} = \frac{c}{Sin 62.8}<em></em>

\frac{11 X sin (62.8)}{sin 35} = C

<em>c =   17.01</em>

<u><em>Final answer</em></u>:-

<em> ∠A = 82.2° , ∠C = 62.8° , c =   17.01</em>

                         

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Answer:

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Step-by-step explanation:

step 1

we know that

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