Answer:
81 9/10
Step-by-step explanation:
The answer is C because it is at the first of four intervals between 0 and 1
Answer:
minimum value is: the left whisker
Step-by-step explanation:
box an whisker plot: left line is the minimum, first part of the box is Q1, where the box has a middle line it is called Median, the other end of the box is Q3, the right line is called the maximum whisker.
Hope this helps
which means there is some integer
for which
.
Because
and
, there are integers
such that
and
, and
We have
, which means there are four possible choices of
:
1, 42
2, 21
3, 14
6, 7
which is to say there are also four corresponding choices for
:
9, 378
18, 189
27, 126
54, 63
whose sums are:
387
207
153
117
So the least possible value of
is 117.
Answer:
s=40
Step-by-step explanation:
Combine s and 1/2.
150−s/2=120+1/4s
Combine 1/4and s.
150−s/2=120+s/4
Move all terms containing s to the left side of the equation.
150−3s/4=120
Move all terms not containing s to the right side of the equation.
−3s/4=−30
Multiply both sides of the equation by −4/3.
−4/3 x (−3s/4)=−4/3 x−30 => S=40
