Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer:
The answer is 30.66, mark me as brainliest
The answer is 169.
169 is a perfect square since 13 times itself (or 13²) is equal to 169.
√279=16.703
√169=13
√154=12.41
√115=10.72
