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kkurt [141]
3 years ago
13

Consider the function, h(x) = –4 x + 2. Determine the asymptote for the function h(x).

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0
There are no horizontal asymptote for this function
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Answer:

it is twice as long(10/12 inches longer

Step-by-step explanation:

1 4/6 make the 6 a 12 and the four a 8. 1= 12/12 so 8+12=20 so 20/12 and 20 is 10/12 more that 10/12 or twice as much.

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How many days until 20 november from 19 october
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November 20, 2019 - October 19, 2020 is 334 days
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Which graph represents the function f(x)=x4+4x3−12x2−32x+64?
sp2606 [1]

f(x)=x^4+4x^3-12x^2-32x+64

The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive

So  as x approaches infinity then y approaches infinity

as x approaches -infinity then y approaches infinity

The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.

Now we check the x intercepts of the first  graph

x intercepts of first graph is -4  and 2

Plug in -4 for x in f(x) and check whether we get 0

f(x)=x^4+4x^3-12x^2-32x+64

f(x)=(-4)^4+4(-4)^3-12(-4)^2-32(-4)+64=0

Now plug in 2 for x and check

f(x)=(2)^4+4(2)^3-12(2)^2-32(2)+64=0

So -4  and 2  are the x intercepts that satisfies f(x)

Hence first option is the graph of f(x)=x^4+4x^3-12x^2-32x+64





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3 years ago
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starting from 1.4 miles away a car drives towards a speed check point and then passes it the car travels at a constant rate of 5
LenKa [72]

Answer: At t=0.015 hours when the car 0.6 miles from the check point.

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Since we have given that

Distance traveled by him towards a speed check point = 1.4 miles

Speed at which he is travelling = 52 miles per hour

Let the time taken by him be x

Since we have the equation

d=1.4-52t

where<em> </em><em>d</em><em> </em>denotes distance

and <em>t </em>denotes time.

If we have given that the car 0.6 miles from the check point.

So, we put the value of <em>d</em> in place of it .

0.6=1.4-52t\\\\0.6-1.4=-52t\\\\-0.8=-52t\\\\0.8=52t\\\\\frac{0.8}{52}=t\\\\0.015=t

So, at t=0.015 hours when the car 0.6 miles from the check point.

5 0
4 years ago
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