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puteri [66]
3 years ago
14

A commuter has $245 in his commuter savings account. This account changes by -$15 each week he buys a ticket. In one time period

, the account changes by-$240. For how many weeks did the commuter buy tickets?
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0
16 would be your answer
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If you apply the changes below to the absolute value parent function, f(x) = 1x1,
inn [45]

If you apply "Shift 5 units to the right" and "Shift 4 units down." to the  absolute value parent function, f(x) = 1x1 you have  g(x)=|x+ 5| f(x) = |x|-4. Option A. This is further explained below.

<h3>What is a function?</h3>

Generally, a function is simply defined as an expression, rule, or law in arithmetic that establishes a link between two variables.

In conclusion, The value is added to x well before the operator with a horizontal shift left.

Hence, f(x) = |x+5|

Because this is a downshift, the vertical movement will be beyond the bars for this function, Hence f(x) = |x|-4

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6 0
2 years ago
The time it takes me to wash the dishes is uniformly distributed between 5 minutes and 12 minutes. What is the probability that
GalinKa [24]

Answer:

0.2857

Step-by-step explanation:

We define the time it takes to do these dishes to be uniformly distributed between the time 5 minutes and 12 minutes.

a = 5 minutes

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Probability of tonight's dish washing being between 6 and 8 minutes

P(6<X<8)

= 8-6/b-a

= 2/12-5

= 2/7

= 0.2857

The probability it will be better 6 and 8 minutes is therefore 0.2857

5 0
3 years ago
Which one of these formulas describes the following sequence?<br><br> 1,5,12,22,35
kati45 [8]

We can find a formula for nth term of the given sequence as follows:

1, 5, 12, 22, 35

The 1st differences between terms:

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The 2nd differences :

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Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form: a n^2 + b n + c, where c is a constant. The coefficients a, b, and the constant c can be found.

We can form the following 3 equations with 3 unknowns a, b, c:

1 = a\cdot1^2 + b\cdot1 + c\\5 = \cdot2^2 + b\cdot2 + c\\12 = a\cdot3^2 + b\cdot3 + c

Solving for a, b, c, we get:

a = 3/2, b = -1/2, c = 0

Therefore, the nth term of the given sequence is:

\boxed{ a_n = \dfrac{3}{2}n^2- \dfrac{1}{2} n}

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