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3 years ago

Please Help Select the correct answer

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

X^1/2 ( x + 3) (x - 6)
= x^1/2 ( x^2 - 3x - 18)
= x^5/2 - 3x^3/2 - 18x^1/2

= (sqrt x)^5 - 3 (sqrt x)^3 - 18x^1/2

Option 1

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Expand the expression and collect like terms.<br><br> - g - 4(2g - 6)

Readme [11.4K]

Answer:

A.T.Q

first we need to open the bracket

,when we open breaket the sign in the bracket will change

so the question is

- g - 4 + 2g + 6

now, we take like terms together

- g + 2g - 4 + 6

g + 2 is the answer by solving

8 0

2 years ago

Help me guys <br> thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

<u>Step 1: Multiply</u>

<u /> $(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

6 0

3 years ago

Read 2 more answers

Tim runs 3 miles every 45 minutes. At this rate, how long did it take Tim to run 18 miles?

geniusboy [140]

Answer: 270 minutes or 4 hours and 30 minutes

Step-by-step explanation: 3x6 =18 and 45 x 6= 270

7 0

2 years ago

I will give a thanks

gogolik [260]

Do what is in the parentheses then add

7 0

3 years ago

Solve the system of equations using substitution and Elimination

juin [17]

<h2>Greetings!</h2>

Answer:

y = $\frac{-18}{7}$ and x = $\frac{50}{7}$

Step-by-step explanation:

To solve simultaneous equations, you need to have the number in front of both x's or y's the same. (signs doesn't matter)

To get -x to -10x we simply need to multiply the first equation by 10:

-x * 10 = -10x

-9y * 10 = -90y

16 * 10 = 160

-10x - 90y = 160

Now we can add the two equations:

-10x + 10x = 0

-90y + 20y = -70y

160 + 20 = 180

-70y = 180

70y = -180

7y = -18

y = $\frac{-18}{7}$

Now plug $\frac{-18}{7}$ into the second equation:

10x + 20( $\frac{-18}{7}$ ) = 20

10x - $\frac{360}{7}$ = 20

Move the $\frac{360}{7}$ over to the other side, making it a positive:

10x = 20 + $\frac{360}{7}$

10x = $\frac{500}{7}$

Divide both sides by 10:

x = $\frac{50}{7}$

So y = $\frac{-18}{7}$ and x = $\frac{50}{7}$

<h2>Hope this helps!</h2>

5 0

2 years ago