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3 years ago

Write (4√81)^5 in exponential form.

Mathematics

1 answer:

kobusy [5.1K]3 years ago

5 0

(4√81)^5=

(4*9)^5=

36^5=

60466176= 6,0466176*10^-7

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ANSWER

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EXPLANATION

The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).

That is the average rate of change is:

$= \frac{f(4) - f(0)}{4 - 0}$

From the graph, f(0) is 0 and f(4) is -4.

We plug in these values to obtain;

$= \frac{ - 4 - 0}{4 - 0}$

This simplifies to;

$= \frac{ - 4}{4}$

$= - 1$

Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1

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Step-by-step explanation:

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$h= \frac{-(-12)}{2(2)}$
$h= \frac{12}{4}$
$h=3$
$k=f(h)=2(3)^2-12(3)+19$
$k=2(9)-36+19$
$k=18-17$
$k=1$
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Now to find our second point, we are going to evaluate our parabola at $x=0$
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