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Kipish [7]
3 years ago
7

Simplify the expression.

le="\frac{5}{\sqrt{3}-2 }" alt="\frac{5}{\sqrt{3}-2 }" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer:

I have attached the work to your problem.

Please see the attachment below.

I hope this helps!

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Michael mows 1/6 of an acre in 1/4 of an hour. How many acres does Michael mow per hour?
Igoryamba
Answer 4/6 of an acre, or 2/3 acres simplified.
5 0
3 years ago
F(x) = a(x - h)power of 3 + k   please describe what a, h and k do within our function. 
Zarrin [17]

F(x) = a(x - h)³ + k

The parent graph is F(x) = x³

k - shifts the parent graph up k-units (or down if it is negative).  This is also called a vertical shift.

h - shifts the parent graph to the right h-units (or left if it is negative).  This is also called a horizontal shift.

a - stretches the parent graph vertically by a factor of "a"

Additonally, the coordinate (h, k) is the center/vertex of the graph.


6 0
3 years ago
Y’all what’s this I’m so confused help
Snowcat [4.5K]

Answer:

x = 66

Step-by-step explanation:

√(x - 2) + 3 = 11

Subtract 3 from both sides:  √(x - 2) = 8

Square both sides:                   x - 2 = 64

Add 2 to both sides:                      x = 66

8 0
3 years ago
I could really use some help
laila [671]
The sequence is increasing by the previous number multiplied by negative 3       (x -3). With this information, the correct answer would be A. -648, 1944, 5832
5 0
3 years ago
Read 2 more answers
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
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