$y < \dfrac{2}{3}x\\\\y=\dfrac{2}{3}x\\\\for\ x=0\to y=\dfrac{2}{3}(0)=0\to(0,\ 0)\\\\for\ x=3\to y=\dfrac{2}{3}(3)=2\to(3,\ 2)\\\\y\geq-x+2\\\\y=-x+2\\\\for\ x=0\to y=-0+2=2\to(0,\ 2)\\\\for\ x=2\to y=-2+2=0\to(2,\ 0)$

$y < \dfrac{2}{3}x$

the dotted line. shadow under the line

$y\geq-x+2$

solid line. shadow above the line

Answer in the attachment (graph C).

8 0

3 years ago

What type of roots will you have if the discriminant is: 36

Paul [167]

Answer:

2 real roots

Step-by-step explanation:

If the discriminant is any positive number, that means the quadratic will have 2 real roots, or solutions.

Since the discriminant, 36, is a positive number, this will apply.

So, if the discriminant is 36, there will be 2 real roots.

4 0

3 years ago

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