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Artemon [7]
3 years ago
9

Write 10 ^ 10 * 10 ^ 0 with a power of 10 with a single exponent using the appropriate exponent rule explain or show your reason

ing
Mathematics
2 answers:
tatiyna3 years ago
6 0

Answer:

10^10

Step-by-step explanation:

Anything to the power of 0 is 1. 10^10 *1 is still 10^10

irina [24]3 years ago
6 0

Answer:

10^10

Step-by-step explanation:

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56 out of 154 in simplest form of a fraction
marissa [1.9K]
We start with 56/154.  Dividing each number by two, we have:

28/77

Dividing each number by seven, we have:

4/11

As the greatest common factor of 4 and 11 is 1, this fraction is in simplest form.  Thus, 56/154 is equal to 4/11.
4 0
3 years ago
Read 2 more answers
(x+6)(x-3) solve by multiplying out and combining like terms
pogonyaev

Answer:

x^2 + 3x - 18

Step-by-step explanation:

In order to solve this problem, I recommend using the FOIL method.

F = Front

O = Outer

I = Inner

L = Last

Start by multiplying the fronts which is x with x, which will give you x^2 (X to the second power).

Then, multiply x and -3, which gives you -3x. (Outer)

Third, multiply 6 and x, which gives you 6x. (Inner)

Finally, multiply 6 and -3, which gives you -18. (Last)

Now, there are like terms in the products that we just did which is 6x and -3x combine them together and you will get 3x.

So your results should be

x^2 + 3x - 18

Hope this helps!

8 0
2 years ago
In words, the scalar product of two vectors can be thought of as the product of the magnitude of ~a with the magnitude of the pr
timama [110]

Answer:

  67.73625

Step-by-step explanation:

The dot (scalar) product is also the sum of products of corresponding vector components.

~a • ~b = 9·2.97 +6.75·6.075 +0·0 = 27.73 +41.00625 = 67.73625

6 0
3 years ago
At time t=0 sec, a tank contains 15 oz of salt dissolved in 50 gallons of water. Then brine containing 88oz of salt per gallon o
maria [59]

Answer:

a) s(t) =400- 385 e^{-\frac{1}{10} t}

b) s(t=25min) =400- 385 e^{-\frac{1}{10}25}=368.397

Step-by-step explanation:

Part a

Assuming that the original concentration of salt is 8 oz/gal and that the rate of in is equal to the rate out = 5 gal/min.

For this case we know that the rate of change can be expressed on this way:

Rate change = In-Out

And we can name the rate of change as \frac{ds}{dt}=rate change

And our variable s would represent the amount of salt for any time t.

We know that the brine containing 8oz/gal and the rate in is equal to 5 gal/min and this value is equal to the rate out.

For the concentration out we can assume that is \frac{s}{50gal}

And now we can find the expression for the amount of salt after time t like this:

\frac{dS}{dt}= 8 \frac{oz}{gal}(5\frac{gal}{min}) -\frac{s}{50gal} 5 \frac{gal}{min} =40\frac{oz}{min}- \frac{s}{10} \frac{oz}{min}

And we have this differential equation:

\frac{dS}{dt} +\frac{1}{10} s = 40

With the initial conditions y(0)=15 oz

As we can see we have a linear differential equation so in order to solve it we need to find first the integrating factor given by:

\mu = e^{\int \frac{1}{10} dt }= e^{\frac{1}{10} t}

And then in order to solve the differential equation we need to multiply with the integrating factor like this:

e^{\frac{1}{10} t} s = \int 40 e^{\frac{1}{10} t} dt

e^{\frac{1}{10} t} s = 400 e^{\frac{1}{10} t} +C

Now we can divide both sides by e^{\frac{1}{25} t} and we got:

s(t) =400 + C e^{-\frac{1}{10} t}

Now we can apply the initial condition in order to solve for the constant C like this:

15 = 400+C

C=-385

And then our function would be given by:

s(t) =400- 385 e^{-\frac{1}{10} t}

Part b

For this case we just need to replace t =25 and see what we got for the value of the concentration:

s(t=25min) =400- 385 e^{-\frac{1}{10}25}=368.397

7 0
3 years ago
6/7 divided by (-14)
Natasha_Volkova [10]

Answer:

=-\frac{3}{49}

Step-by-step explanation:

\frac{6}{7} \div -14\\\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}\\\\=-\frac{\frac{6}{7}}{14}\\\\\mathrm{Apply\:the\:fraction\:rule}:\\\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\times\:a}\\\\\frac{\frac{6}{7}}{14}=\frac{6}{7\times\:14}\\\\=-\frac{6}{98}\\\\\mathrm{Cancel\:the\:common\:factor:}\:2\\\\=-\frac{3}{49}

4 0
3 years ago
Read 2 more answers
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