Please help with 18 19 and 20
1 answer:
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We are given
A dog runs from point O to B
t(OA)=2.3 s
t(OC)=4.1 s
now, we can find time between A and C
t(AC)=t(OC)-t(OA)
t(AC)=4.1-2.3
t(AC)=1.8 s
we are given
distance between A and C is 4m
so,
d=4m
now, we can find average velocity between A and C
we can plug values
so, option-C..................Answer
Answer:
On the graph B, at 0 seconds the graph will be <u>at </u>
The graph will be <u>going down</u> until 2 seconds, when the diver reaches her deepest point. At 2 seconds the height of the graph will be -8ft.
Step-by-step explanation:
In graph B we are measuring the distance from the surface, that is we are setting the surface to be y=0. Thus if the diver reaches her deepest point 8ft down, she will be below y=0 and at -8ft.
Thus, in shape the graph B will be similar to graph A, but it will be shifted downed by 8ft.